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How many electrons per second pass through a section of wire carrying a current of `0.7A`? |
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Answer» We known that `I = (q)/(t) = ("ne")/(t) , therefore, n = (it)/(e ) = (0.7xx1)/(1.6x10^(-19)` So number of electrons in `n = 0.44xx10^(19)` |
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