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How many divisors (including 1, but excluding 1000) are there for the number 1000? |
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Answer» 2 | 1000 2 | 500 2 | 250 5 | 125 5 | 5 | 1 1000= 2*2*2*5*5 follow above procedure to find number of divisors for any number including one and itself in this PROCESS we use only prime NUMBERS to divide a specific number until we get one as shown in picture we can write 1000 as (2^3)×(5^3) = 1000 for any number 'n' after primefactorization we get n = (2^a)×(3^b)×(5^c)×(7^d)...... number of divisors for n = (a+1)×(b+1) ×(c+1)........ similarly for 1000 = (3+1)×(3+1) = 16(including 1 and itself(1000)) excluding 1000 we get only 15
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