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How many different numbers greater than 60000 can be formed with the digits 0, 2, 2, 6, 8? (a) 144 (b) 48 (c) 24 (d) 288 |
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Answer» (c) 24 Numbers greater than 60000 will have either 6 or 8 in the TTh place and will consist of 5-digits. If the digit 6 occupies the TTh place, the remaining 4 places can be occupied in \(\frac{4!}{2!}\) ways. (∵ There are two 2’s) Number of numbers beginning with 6 = \(\frac{4!}{2!}\) = 12 Similarly, number of numbers beginning with 8 = \(\frac{4!}{2!}\) = 12 ∴ Number of different numbers greater than 60000 formed with digits 0, 2, 2, 6, 8 = 12 + 12 = 24. |
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