1.

How many atoms of mercury are present in 1g of mercury

Answer»

Molecular MASS of mercury = 80 g
Given mass = 1
No. of atoms = (Given mass/ Molar mass) X AVAGADRO's no,
                      = (1/80) x 6.022 x 10^23
                      =0.075275 x 10^23
                     = 7.5275 x 10^21


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