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How many atoms of each element are there in 9.8g of sulphuric acid. Plz no spam otherwise will be reported. |
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Answer» For H: 9.8gH2SO4(1molH2SO498gH2SO4)(2molH1molH2SO4)(6.022⋅1023atms1molH) =1.2004⋅1023 ATOMS / MOL H.For S: 9.8gH2SO4(1molH2SO498gH2SO4)(1molS1molH2SO4)(6.022⋅1023atms1molS) =6.022⋅1022 atoms / mol S.For O: 9.8gH2SO4(1molH2SO498gH2SO4)(4molO1molH2SO4)(6.022⋅1023atms1molO) =2.4088⋅1023 atoms / mol O. |
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