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How many atoms are present in 50g of caco3 |
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Answer» Hence, we have 50/100= 0.5mol of CaCO3. From the formula, we can see that in 1 mol of CaCO3, 3 mol of OXYGEN atoms are present. Hence, in 0.5 mol, we have 1.5 mol of oxygen atoms. 1 mol=6.022*10^23 particle, which, by MATH, GIVES us 9.011*10^23 atoms of oxygen in 50g of CaCO3 |
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