how many atoms are present in 10g og o

1.	how many atoms are present in 10g og o
Answer» ×1023 atoms of OXYGEN Explanation:The question is incomplete. We have to find out the no. of atoms of oxygen in 10 G of water.First we need to find out moles of water Moles = mass / molar massmole of water = 10 /(1.0082+16) = 10 /18 = 0.56Now, as we know 1 mole contains 6.022 × 10 ^23 atoms or MOLECULES Now from the formula we know, 2 mole of water contains 1 mole of oxygen then moles of oxygen in 10G of water = 0.28 atoms of oxygen in 10g of water = 0.28 6.022 × 10 ^23 = 1.6856 ×1023 atoms of oxygen

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