How many atoms are in 3.58 mol c2h6

1.	How many atoms are in 3.58 mol c2h6
Answer» Explanation: In 1 MOLE, no. of C atoms =2 × 6.022 × 10^23 no. of H atoms = 6 × 6.022 × 10^23 THEREFORE, in 3.58 moles, no. of C atoms = 2 × 6.022 × 10^23 × 3.58 = 43.11752 × 10^23 no. of H atoms = 6 × 6.022 × 10^23 × 3.58 = 129.34256 × 10^23 Total no. of atoms = 10^23 ×(43.11752 + 129.34256) = 172.46008 × 10^23

Answer»

Explanation:

In 1 MOLE,

no. of C atoms =2 × 6.022 × 10^23

no. of H atoms = 6 × 6.022 × 10^23

in 3.58 moles,

no. of C atoms = 2 × 6.022 × 10^23 × 3.58 = 43.11752 × 10^23

no. of H atoms = 6 × 6.022 × 10^23 × 3.58 = 129.34256 × 10^23

Total no. of atoms = 10^23 ×(43.11752 + 129.34256)

= 172.46008 × 10^23

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