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How many alpha and beta- particles are emitted when uranium nucleus (""_(92)^(238)U) decay to ""_(82)^(214)Pb ? |
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Answer» SOLUTION :Let n be the number of `alpha` - particles and m be the number of `beta` - particles emitted. `""_(92)U^(238)RARR ""_(82)Pb^(214)+n_(2)He^(4)+m""_(-1)e^(0).` As mass is conserved , 238 = 214 + 4N + m (0) `= 214 + 4n implies 4n = 24 , n = 6` As charge is conserved , 92 = 82 + 2n + m (-1) 10 = 2 (6) - m`(:.n = 6) implies m = 2 ` `:. 6 alpha` particles and `2 beta` - particles are emitted |
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