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How is the presence of `SO_2` detected? |
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Answer» `SO_2` acts as a reducing agent hence `SO_2` turns pink coloured `KMnO_4` to colourless solution due to reduction of `MnO_4^(ɵ)` to `Mn^(2+)` `[MnO_4^(ɵ)+8H^(ɵ)+5e^(ɵ)toMn^(2+)+4H_2O]xx2` `underline[SO_2+2H_2OtoSO_4^(2-)+4H^(o+)2e^(ɵ)]xx5)` `underline(2MnO_4^(ɵ)+2H_2O+5SO_2to2Mn^(2+)+5SO_4^(2-)+4H^(o+))` |
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