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How is Graham's Law of Diffusion calculated? |
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Answer» tion:Graham’s law of diffusion STATES that the rate of diffusion of a gas at a given TEMPERATURE is inversely proportional to the SQUARE root of its molecular mass, m.I.e. R α 1/√mAlso, vapour density (ρ) = molar mass (g)/molar VOLUME (v)Molar mass = vapor density (ρ) x molar volume (v)Therefore, R α 1/√ρvFor two gases with molecular masses m1 and m2 ; and rates of diffusion R1 and R2:R1/R2 = √m2/√m1 – (1)R1/R2 = √ρ2v2 /√ρ1v1 – (2)Also, rate of diffusion = volume/time I.e. the GREATER the rate, the shorter the time.Comparing the rates of diffusion of equal volumes of two gases in times t1 and t2, we have R1 = V/t1 and R2 = V/t2 |
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