1.

How fast should a man weighing 600N run so that his kinetic energy is 750J

Answer»

For, v = velocity, m = mass of man.

Kinetic Energy (KE) = 1/2 m v^2

So, v = (2 KE / m)^1/2

v = (2 . 750 / 60)^ 1/2

v = (25)^1/2 = 5 m/s



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