1.

How does the electric field change with the effect of the dielectric when the battery remains connected across the capacitor?(a) Increases(b) Decreases(c) Remains unchanged(d) ZeroThis question was posed to me in an interview.My doubt is from Effect of Dielectric on Capacitance in portion Electrostatic Potential and Capacitance of Physics – Class 12

Answer»

Correct choice is (c) Remains unchanged

Best explanation: As the POTENTIAL difference remains unchanged, so the electric FIELD E0 between the CAPACITOR plates remain unchanged.

E = \(\frac {V}{d}\) = \(\frac {V_0}{d}\) = E0.



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