1.

How does refractive index (mu) of a material vary with respect to wavelenght (lambda). (A and B are constants).

Answer»

`MU = A + (B)/(lambda^(2))`
`mu = A + Blambda^(2))`
`mu = A + (B)/(lambda)`
`mu = A = B lambda`

SOLUTION :ACCORDING to cauchy.s relation, `mu = A + (B)/(lambda^(2))`


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