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How do yout explain the presence of five `-OH` groups in glucose molecule? |
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Answer» Glucose on reaction with acetic anhydride produces glucose pentaacetate. `overset(" "CHO)overset(|)underset(" "CH_(2)OH)underset(|)(" "(CHOH)_(4))overset("Acetic anhydride")rarroverset(" "CHO)overset(|)underset(" ""Glucose pentacetate")underset(" "CHOAc)underset(|)(" "(CHOAc)_(4))` This reaction explain presence of five -`OH` groups. |
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