How Do You Prove That By Default, Case Object Is Serializable And Nor

1.	How Do You Prove That By Default, Case Object Is Serializable And Normal Object Is Not?
Answer» Yes, By DEFAULT, CASE Object is Serializable. But normal object is not. We can prove this by using isInstanaceOf method as SHOWN below: SCALA> object MyNormalObject defined object MyNormalObject scala> MyNormalObject.isInstanceOf[Serializable] res0: Boolean = false scala> case object MyCaseObject defined object MyCaseObject scala> MyCaseObject.isInstanceOf[Serializable] res1: Boolean = TRUE Yes, By Default, Case Object is Serializable. But normal object is not. We can prove this by using isInstanaceOf method as shown below: scala> object MyNormalObject defined object MyNormalObject scala> MyNormalObject.isInstanceOf[Serializable] res0: Boolean = false scala> case object MyCaseObject defined object MyCaseObject scala> MyCaseObject.isInstanceOf[Serializable] res1: Boolean = true

How Do You Prove That By Default, Case Object Is Serializable And Normal Object Is Not?

Answer»

Yes, By DEFAULT, CASE Object is Serializable. But normal object is not. We can prove this by using isInstanaceOf method as SHOWN below:

SCALA> object MyNormalObject
defined object MyNormalObject

scala> MyNormalObject.isInstanceOf[Serializable]
res0: Boolean = false

scala> case object MyCaseObject
defined object MyCaseObject

scala> MyCaseObject.isInstanceOf[Serializable]
res1: Boolean = TRUE

Yes, By Default, Case Object is Serializable. But normal object is not. We can prove this by using isInstanaceOf method as shown below:

scala> object MyNormalObject
defined object MyNormalObject

scala> MyNormalObject.isInstanceOf[Serializable]
res0: Boolean = false

scala> case object MyCaseObject
defined object MyCaseObject

scala> MyCaseObject.isInstanceOf[Serializable]
res1: Boolean = true

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