How do we apply (4n+2)π rule except for benzene to find out which is

1.	How do we apply (4n+2)π rule except for benzene to find out which is aromatic
Answer» Explanation: when the number of its π-electrons equals 4n + 2 where N is a non-negative integer, although clearcut examples are really only established for values of n = 0 up to about n = 6. Criteria for simple aromatics are: the molecule must have 4n + 2 electrons in a conjugated system of p orbitals (usually on sp2-hybridized atoms, but sometimes sp-hybridized); the molecule must be (close to) planar (p orbitals must be ROUGHLY PARALLEL and ABLE to interact, IMPLICIT in the requirement for conjugation); the molecule must be cyclic (as opposed to linear); the molecule must have a continuous ring of p atomic orbitals (there cannot be any sp3 atoms in the ring, nor do exocyclic p orbitals count). hope it helps!! mark it as the brainliest!!✌

How do we apply (4n+2)π rule except for benzene to find out which is aromatic

Answer»

Explanation:

when the number of its π-electrons equals 4n + 2 where N is a non-negative integer, although clearcut examples are really only established for values of n = 0 up to about n = 6.

Criteria for simple aromatics are:
the molecule must have 4n + 2 electrons in a conjugated system of p orbitals (usually on sp2-hybridized atoms, but sometimes sp-hybridized);
the molecule must be (close to) planar (p orbitals must be ROUGHLY PARALLEL and ABLE to interact, IMPLICIT in the requirement for conjugation);
the molecule must be cyclic (as opposed to linear);
the molecule must have a continuous ring of p atomic orbitals (there cannot be any sp3 atoms in the ring, nor do exocyclic p orbitals count).

mark it as the brainliest!!✌