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How do u factorise tge following pq - 4p +3q - 12 |
Answer» ANSWER:
GIVEN:
TO FIND:
SOLUTION:= pq-4p+3q-12 = (pq-4p)+(3q-12) = p(q-4)+3(q-4) = (q-4)(p+3) ADDITIONAL INFORMATION:=> (q-4)(p+3) = 0 Either (q-4) = 0 => q = 4 Either (p+3) = 0 => p = (-3) NOTE:Some important formulas: (a+b)² = a²+b²+2ab (a-b)² = a²+b²-2ab (a+b)(a-b) = a²-b² (a+b)³ = a³+b³+3ab(a+b) (a-b)³ = a³-b³-3ab(a-b) a³+b³ = (a+b)(a²+b²-ab) a³-b³ = (a-b)(a²+b²+ab) (a+b)² = (a-b)²+4ab (a-b)² = (a+b)²-4ab |
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