How do I find out what the pH of a solution made of 500ml 0.1M HCl and

1.	How do I find out what the pH of a solution made of 500ml 0.1M HCl and 500ml 0.1M NaOH is?
Answer» . Equivalents of HCl =0.1x2x 500 =100No.of m. Equivalents of NaOH =500x0.1= 50.So 50 m. Equivalents of NaOH will react and neutralise 50 m. MOLES of HCl and the RESULTANT 1000 ML of the solution will contain (100–50)=50 m. moles of HCl.The concentration of 1000 ml.of solution will be 100/1000=0.05N HCl.The pH of this Solution= - log (0.05)=1.30(APPROX)plz MARK my answer as the branieliestplz

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