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How can three resistors of resistances 2Ω, 3 Ω, and 6Ω be connected to give a total resistance of (i) 4 Ω, (ii) 1 Ω ? |
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Answer» Answer: To obtain a TOTAL RESISTANCE of 4 Ω from three resistors of given resistances, Firstly, CONNECT the TWO resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω. ... ⇒ 1/R = 1 Ω. Explanation: hope it was HELP full |
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