1.

how can three resistance of 2,3 and 6 ohms be connected so as to give a total resistance of 1 ohm? show the working of your solution​

Answer»

ANSWER :

Parallel COMBINATION.

SolutioN :

Let's,

  • R1 = 2Ω.
  • R2 = 3Ω.
  • R3 = 6Ω.

Now,

♢ Let's try to CONNECT all THREE RESISTANCE in Parallel Combination :

\tt \dagger \:  \:  \:  \:  \: \dfrac{1}{R_p}= \dfrac{1}{R_1} +  \dfrac{1}{R_2} + \dfrac{1}{R_3} ... \dfrac{1}{R_n}

\tt \dashrightarrow \:  \: \dfrac{1}{R_p}= \dfrac{1}{2} +  \dfrac{1}{3} + \dfrac{1}{6}

\tt \dashrightarrow \:  \: \dfrac{1}{R_p}=  \dfrac{3 + 2 + 1}{6}

\tt \dashrightarrow \:  \: \dfrac{1}{R_p}=  \dfrac{ \cancel6}{ \cancel6}

\tt \dashrightarrow \:  \: \dfrac{1}{R_p}= 1\Omega.

\dashrightarrow \:  \: \:  \:  \:  \boxed{  \tt R_p=  1\Omega. }

Diagram :

----------------| 2Ω |-----------------

----------------| 3Ω |-----------------

----------------| 6Ω |-----------------

Therefore, the net resistance 1Ω which you get when we connect R1, R2 and R3 in Parallel Combination.



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