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How are the two alpha angles equal​

Answer» TION:GIVEN EXPRESSION, SIN 2 α+sin 2 β+sin 2 γ=(1−cos 2 α)+(1−cos 2 β)+(1−cos 2 γ)=3−cos 2 α+cos 2 β+cos 2 γ=3−1=2(∵cos 2 α+cos 2 β+cos 2 γ=1)


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