1.

Horizontal component of earth’s magnetic field at a place is √ times its vertical component. What is the value of angle of dip at that place?

Answer»

Given H = √3V ⇒ tanθ = \(\frac{V}{H}\) = \(\frac{1}{\sqrt{3}}\) 

⇒ Angle of dip, θ = tan-1\(\Big(\frac{1}{\sqrt{3}}\Big)\) = 30°



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