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Horizontal component of earth’s magnetic field at a place is √ times its vertical component. What is the value of angle of dip at that place? |
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Answer» Given H = √3V ⇒ tanθ = \(\frac{V}{H}\) = \(\frac{1}{\sqrt{3}}\) ⇒ Angle of dip, θ = tan-1\(\Big(\frac{1}{\sqrt{3}}\Big)\) = 30° |
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