1.

Hola!!Calculate the angular speed of the (I) Second hand and (II) minute hand of a watch.

Answer»

Solution :-

We have to calculate the angular speed of

(i) Second hand

As second hand COMPLETE on ROTATION in 60 sec

FREQUENCY = 1/60

Now as we know that

ω = 2πf

\omega = 2 \times \dfrac{22}{7} \times \dfrac{1}{60}

\omega = \dfrac{44}{420}

\omega = \dfrac{11}{105}

\omega = 0.104761

\omega = 0.1048 \: rad/sec

\large{\boxed{\sf{\omega = 1.048 \times 10^{-1} \: rad/sec}}}

(ii) Minutes hand

As MINUTE hand complete on rotation in 60 × 60

= 3600 sec

→ Frequency = 1/3600

Now as we know that

ω = 2πf

\omega = 2 \times \dfrac{22}{7} \times \dfrac{1}{3600}

\omega = \dfrac{44}{25200}

\omega = \dfrac{11}{6300}

\omega = 0.0017460

\omega =  0.001746\: rad/sec

\large{\boxed{\sf{\omega = 1.746 \times 10^{-3}\: rad/sec}}}



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