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Hlw everyone up here!!Maths//--QUESTION:- For p(x) = (x-1) (x-2) Find p(2)❓❓❓​

Answer»

p(x) =  {x}^{2} - 2x - 1x +2 \\ p(x) = x(x - 2) - 1(x - 2) \\ p(x) = x - 1 = 0 \:  \:  \:  \:  \: x - 2 = 0 \\ p(x) = x = 1 \:  \:  \:  \:  \: x = 2 \: \: are \: the \: zeroes \: of \: the \: polynomial \\ p(2) = (2 - 1)(2 - 2) \\ p(2) = (1)(0) \\ p(2) = 0 \\ i \: hope \: its \: help \: you \: \\ plz \: mark \: me \: as \: a \: brainest



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