Hlo ....plzzz solve question number 6 nd 7✌️✌️

1.	Hlo ....plzzz solve question number 6 nd 7✌️✌️
Answer» $\huge\red{\mathfrak{Hello..!!}}$ $\huge\pink{\mid{\underline{\overline{\tt Answer6:-}}\mid}}$ $\huge\boxed{\fcolorbox{red}{yellow}{Answer}}$ $r = 5cm$ Step-by-step explanation: Let the RADIUS of the CIRCLE be r. In ∆AOM OM is perpendicular on AB. $AM = \frac{1}{2} AB \\ = \frac{1}{2} AB \\ = \frac{1}{2} \times 8 \\ = 4cm \\ OM = (r - 2cm) \\ OA = r \\ {OA}^{2} ={AM}^{2}+{OM}^{2}$ ${r}^{2} = {4}^{2} + {(r - 2)}^{2}$ $=16+{r}^{2}-2×r×2+{2}^{2}$ $OA=16-4r+4$ $OA=20-4r \\4r=20 \\r=5cm$ $Shahnawaz_Here$

Answer»

$\huge\red{\mathfrak{Hello..!!}}$