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Hiii any one are free ✌✌⛤⛤⛤⛤ A constant force acts for 5 second a body of mass 5 quitals and then ceased to act. during next 5 seconds the body describes 100m . find the magnitude of force.

Answer» CM = 5 quitalsNext 5 SEC thts t = 5 sec DISTANCE = 100mForce = mass * acceleration VELOCITY = d/t= 100/5= 20m/sNow acceleration = v - u / t= 20 - 0 / 5= 4 m/s ²F = mamass = 5 QUINTAL = 500 kgtherefore 500 * 4= 2000NHope this helps


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