1.

Hii friendszzzz......hw r u all?!!-------a question solve fastt.Question---:-find the range --- attachment file--class 11thchapter---relation n functions

Answer»

[1]

=> f(x) = 2-3x

let's

=> f(x) = y

=> 2 - 3x = y

=> 2 - y = 3x

=> X = (2 - y)/3

Given THA "x>0"

so

=> (2-y)/3 > 0

=> 2 - y > 0

=> 2 > y

=> y < 2

HENCE

RANGE of f(x) is = (-infinity, 2)
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[2]

=> f(x) = x² + 2

X is a real no..

Given that X is a real no. so square of a real no. always be positive or 0 .

So we can say that :-

=> x² ≥ 0

Adding 2 both Side

=> x² + 2 ≥ 0 + 2

=> x² + 2 ≥ 2

=> f(x) ≥ 2

Hence

The range of f(x) is = [2 , infinity ]
______________________[ANSWER]

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