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Answer» 1).The balanced equation for the above reaction is as follows:=) 2H2+ O2------) 2H2OFrom the above its clear that 2 mole H2 reacts with 1 mole O2.Molar mass of H2= 2gMolar mass of O2= 32gThis implies, 4g H2 reacts with 32g O2=) 3g H2 reacts with =) (32/4)× 3g of O2=) 24gAs the given amount of O2 is more required therefore O2 is excess Reagent & H2 is limiting Reagent.(2).2 mole of H2 gas reacts with to form 2 mole of water molecule therefore,=) 4g of H2 produces = 36G of waterSo, the amount of H2O PRODUCED by 3g H2 = (36/4)× 3= 27gHence, 27g of water will be produced during this reaction.(3).As, 24g of O2 has been UTILISED during the reaction & 29g of oxygen was supplied therefore AMOUNTS of O2 gas left is (29-24) = 5ghope it helps ☺️ |
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