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hi friends please solve each and every question and please do not give irrelevant answers or else it would be reported for sure .... please answer fast .....this is for class 10 ......

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Answer:

Q 5] ∅ =45    {SIN45 = 1/\sqrt{2} and COS 45 = 1/\sqrt{2}}

Q6] sinA =1/2 when A=30° HENCE COTA = cot30 =\sqrt{3}/1

Q7] if cos(α+β) = 0 then α+β = 90 ---eq1 (∵cos(90) = 0)

         sin A = cos 90-A hence

         sin (α-β) = cos (90-(α-β))

                       = cos (α+β-α+β)                  [ -×- = +][from eq 1]

                       = cos (2β)

Q8] sorry for this

Step-by-step explanation:


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