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Hi friends please help me in this question :Book : M.L. Aggarwal Class: 9Question 1:A rectangular plot of land measures 41 metres in length and 22.5 metres in width. A boundary wall to metres high is built all around the plot at a distance of 1.5 m from the plot. Find the inner surface area of the boundary wall. ❌Spam not allowed ❌ |
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Answer» Step-by-step explanation: GIVEN:-The wall is built 1.5 m from the PLOT so the length and WIDTH of wall will be 41 + 2(1.5) = 44m 22.5 + 2(1.5) = 25.5m. TO FIND:-Inner surface area of the boundary wall PROOF:-Inner area of wall = 2h (L + b) = 2 (2) (44 + 25.5) = 278m^2 ANSWER:-The inner surface area = 278m^2 |
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