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Hi friendhow are you all plzz answer me this question experts1. factorise the following(i) x³-y³+1+3xy(ii)2√2x³+8y³-27z³+18√2xyz2.find the value of (x-2a)³+(x+3b)³+(x-c)³-(x+3b)(x-c),when 3x=2a-3b+c.3.factorise:27a³+8b³+54a²b+36ab²+729

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Answer:

Step-by-step explanation:

3)27a^3+8b^3+54a^2b+36ab^2

= (3A)^3+(2b)^3+3 (3a)^2 (2b)+3 (3a)(2b)^2

=(3a+2b)^3

1)a^3 + b^3 + c^3 - 3ABC = (a+b+c)(a^2+b^2+c^2-ab-bc-ca)  

Here a=x, b=-y, c=-1

Now,  

x^3-y^3-1-3xy = (x-y-1) (x^2+y^2+1+xy-y+x)


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