Hi find the equation of locus of point equidistant from the points (1,

1.	Hi find the equation of locus of point equidistant from the points (1,3) (5,7)
Answer» <P> $\textbf{Given:}$ $\textsf{Points are (1,3) and (5,7)}$ $\textbf{To <klux>FIND</klux>:}$ $\textsf{The locus of a point which is equidistant from the}$ $\textsf{given two points}$ $\textbf{Solution:}$ $\textsf{Let the given points be A(1,3) and B(5,7)}$ $\textsf{Let P(h,k) be the moving point}$ $\textsf{As per given data,}$ $\mathsf{PA=PB}$ $\mathsf{\sqrt{(h-1)^2+(k-3)^2}=\sqrt{(h-5)^2+(k-7)^2}}$ $\textsf{Squaring on bothsides, we get}$ $\mathsf{(h-1)^2+(k-3)^2=(h-5)^2+(k-7)^2}$ $\mathsf{h^2+1-2h+k^2+9-6k=h^2+25-10h+k^2+49-14k}$ $\mathsf{10-2h-6k=74-10h-14k}$ $\mathsf{8h+8k-64=0}$ $\mathsf{h+k-8=0}$ $\therefore\mathsf{The\;locus\;of\;P\;is}$ $\boxed{\mathsf{x+y-8=0}}$ $\textbf{Find more:}$ Find the locus of point P if PA=PB. Coordinates of. A(4,0) and B(-4,0) brainly.in/question/18378699 The locus of the point which is equidistant from the points (-2,2) and (3,0) is brainly.in/question/34702598