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Heya!!!✨ maths Aryabhatta ✨find the two parallel sides of trapezium whose area is 1.6 m², altitude is 10 dm and one of the parallel sides is longer than the other by 8 dm.

Answer»

hiii!!!

here is ur answer...

GIVEN :-

altitude of the trapezium = 10dm = 1m

ATQ, one of the parallel side is 8DM (0.8m) longer than the other.

let the shorter parallel side be x.

therefore the longer parallel side is x + 0.8

area of the trapezium = 1.6m²

==> 1/2 × H ( b1 + b2 ) = 1.6m²

==> 1/2 × 1 ( x + x + 0.8 ) = 1.6m²

==> 1/2 ( 2x + 0.8 ) = 1.6m²

==> 2x + 0.8 = 1.6/1 × 2/1

==> 2x + 0.8 = 3.2

==> 2x = 3.2 - 0.8

==> 2x = 2.4

==> x = 2.4/2

==> x = 1.2

hence, shorter parallel side of the trapezium = 1.2m

and longer parallel side = 1.2 + 0.8

= 2m

hope this HELPS..!!



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