1.

Hey mateplz answer fast1] d [logx] / dx2] d [e^x lnx} / dxdo differentiationFASTT

Answer»

HEY mate

Hey mate

1) We KNOW theorem that

\frac{d \: log_{x} }{dx } = \frac{1}{x}

which is final result of first part.

Note:

lnx = log_{n}(x)

2) Here we will use FOLLOWING formula

\frac{d \: uv}{dx} = u \frac{dv}{dx} + v \frac{du}{dx}

On keeping in mind all THEOREMS of differentiation we get differentiation as follows:

ex/x+lnx.ex

hope it HELPS


Discussion

No Comment Found

Related InterviewSolutions