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Hey Guys Help Please♥️ Charges q1 = 100 u C and q2= 50 u C are located in xy-plane at positions r1 = 3.0 j andr2 = 4.0 i respectively. Where the distance is measured in meters. Calculate the forceon q2(a) 1.8 N(b) 2.5 N(C) ZN(d) 8N |
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Answer» 9NExplanation:DISTANCE between the charges Q1 and q2 __________ = √(0-4)²+(3-0)² = √25 r = 5 metersgiven q1 = 100uC =1× 10^(-4) C q2 = 50uC = 5×10^(-5) C=> Force(F) = (1/4π€0) q1q2/r² = 9×10^9×10^(-4)×5×10(-5)/5 = 9 N=> all options are false.=> The force between the charges is 9N HOPE this HELPS you |
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