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Answer:

Given:-

  1. ∆ PQR is an isosceles triangle.
  2. PQ = PR
  3. angle PQR = 40°
  4. PS is the median.

To find :-

  1. angle QPS

Solution:-

  • angle PQS = angle PRS = 40° ( angles on the EQUAL SIDES of a triangle are equal )
  • angle QPR = 180° - 80° = 100° ( Angle Sum Property of a Triangle )
  • angle QPS = 1/2 angle QPR ( PS is the median and PS bisects angle P )
  • angle QPS = 100° / 2 = 50°

Hence, the VALUE of angle QPS is 50°.

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