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Hey ! ✌️ Explain Air column and Fluid column.?Don't spam or copy.!

Answer»

According to me. , the coulomb force between two CHARGES q1, q2 is:

F =kq1q2/r^2

k = coulomb’s constant = 1/4πεε0

ε0 = permittivity of EMPTY space

ε = relative permittivity of the material in which the charges are immersed

r = distance between charges

for vacuum ε=1 and for air also, to a very good approximation ε=1.

For water , at room temperature ( 20C) ε = 80.

Therefore, the force between the charges q1, q2 will be 1/80 its value in air.

Hence FW, the force in water will be:

so Fw = 80/80 = 1N.

it's the answer I think
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