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Help with it pls, best answer is brainliest. |
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Answer» ONG>Step-by-step EXPLANATION: LHS = \frac{Sin^2A}{COS^2A} + \frac{Cos^2A}{Sin^2A} Cos 2 A Sin 2 A
+ Sin 2 A Cos 2 A
= \begin{gathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{gathered} = Cos 2 A.Sin 2 A Sin 4 A+Cos 4 A
Using a 2 +b 2 =(a+b) 2 −2ab a=Cos 2 A&b=Sin 2 A = Cos 2 ASin 2 A (Sin 2 A+Cos 2 A) 2 −2Sin 2 ACos 2 A
Sin 2 A+Cos 2 A=1 = Cos 2 ASin 2 A 1−2Sin 2 ACos 2 A
\begin{gathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{gathered} = Cos 2 ASin 2 A 1
−2 =RHS
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