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HELP PLEASE?!What is the equation of line B?

Answer»

The two points from which LINE B passes are →

☉ (6,-2)

☉ (-3,1)

[Note : You may also TAKE other points from which line B passes but those points should be accurate.]

Now ,

The line B passes through the points (6, -2) and (-3,1)

So, first of all we need to find the slope of the line B.

The formula for finding the slope of a line is as follows :-

\implies \: \frac{y2 \: - \: y1}{x2 \: - \: x1} \\

Here ,

y2 = 1 \\ y1 = - 2 \\ x2 = - 3 \\ x1 = 6

Now , substituting the values in the equation we get,

\implies \: \frac{1 - ( - 2)}{ - 3 - 6} \\ \\ \implies \: \frac{1 + 2}{ - 9} \\ \\ \implies \: \frac{3}{ - 9} \\ \\ \implies - \frac { 1}{3}

So the slope of the GIVEN line is -⅓

Therefore the equation of the line passing through the point (6,-2) with slope = -1/3 is as follows :—

➜ y - y1 = m ( x - x1 )

➜ y - (-2) = -1/3 (x - 6)

➜ 3(y+2) = 6-x

➜ 3y + 6 = 6 - x

★ 3y + x = 0

Hence the required equation of the line B is 3y + x =0

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