Help me with qs 4b) i) and ii) and Qs 5

1.	Help me with qs 4b) i) and ii) and Qs 5
Answer» Answer: 4 a) In TRIANGLE ABD and triangle ADC angle ADB = angle ADC ( both 90° ) AB = AC ( given ) AD = AD ( common ) triangle ABD congruent triangle ADC ( RHS cong. RULE ) So , BD = DC ( C.P.C.T ) BC = 2× BD = 2 × ( 6x - 4 ) Area of triangle = 1/2 × base × alt. = 1/2 × 2 ( 6x - 4 ) × ( 2x + 7 ) = ( 6x - 4 ) × ( 2x + 7 ) = 12x² + 42x - 8x - 28 = (12x² + 34x - 28 ) units²

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Answer:

4 a) In TRIANGLE ABD and triangle ADC

angle ADB = angle ADC ( both 90° )

AB = AC ( given )

AD = AD ( common )

triangle ABD congruent triangle ADC ( RHS cong. RULE )

So , BD = DC ( C.P.C.T )

BC = 2× BD = 2 × ( 6x - 4 )

Area of triangle = 1/2 × base × alt.

= 1/2 × 2 ( 6x - 4 ) × ( 2x + 7 )

= ( 6x - 4 ) × ( 2x + 7 )

= 12x² + 42x - 8x - 28

= (12x² + 34x - 28 ) units²

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Help me with qs 4b) i) and ii) and Qs 5

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