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Help me solving this question please |
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Answer» distance penetrated = 7.5 m, average retardation force = 7.5 NExplanation:Given that, Mass of the bullet is 0.005 Kg. Initial velocity of the bullet is 150 m/s. TIME of PENETRATION is 1/10 sec. Final velocity of the bullet is 0 m/s. So, distance of penetration = ut + 1/2at^2 s = 150(1/10) + 1/2[(0-150)/1/10](1/10)^2 s = 7.5 m average retardation force = mass * ACCELERATION of retardation F = m*a = 0.005*(0-150)/(1/10) = 7.5 N HOPE THE ANSWER HELPED. |
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