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Hello sir/ma'am My doubt is that for an isothermal reversible process why should ∆H = 0? Shouldn't it have some other value because there is a change in volume?( ∆H=∆U+P∆V, ∆U=0 )

Answer» Hello sir/ma'am
My doubt is that for an isothermal reversible process why should ∆H = 0? Shouldn't it have some other value because there is a change in volume?( ∆H=∆U+P∆V, ∆U=0 )


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