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Hello friends, tell me if x+y+z=0 then prove that x³ +y³+z³=3xyz |
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Answer» HELLO FRIEND here's ur answer ◆●◆x^3+y^3+z^3-3xyz= (x+y+z)* (x^2+y^2+z^2-xy-xz-yz)+ 3xyz because you say that● x+y+z=0 ●then THEREFORE ◆●◆x^3+y^3+z^3-3xyz= (0)*(x^2+y^2+z^2-xy-xz-yz) =0 and thus•••,x^3+y^3+z^3=3xyz•• |
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