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♥ Hello Friends !!! ♥ Answer this Question ⤵⤵A boy standing in a quarry claps his hands sharply once every second and heard an echo from the face of the opposite cutting. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of sound = 360 m/s ) .❎ No Spam Answers ❎First and best => Brainliest |
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Answer» n :-A boy standing in a quarry claps his hands sharply once every second and heard an ECHO from the face of the opposite CUTTING. He moves until the echo is heard midway between the claps. How far is he then from the reflecting surface ( velocity of SOUND = 360 m/s ) .ANSWER :-90 mStep by STEP :-Given :The boy claps every second.So in 1 s he claps 1 time .Time He moves until the echo is heard midway between the claps.Hence the echo is heard in 0.5 sThis is because he claps in 1 s and the midway will be 1/2 s = 0.5 s.Formula Speed = distance / timeTime he heard the echo = 0.5 sLet Distance from the surface be d.The distance traveled by echo is 2 d since it has to MOVE twice from the source to reflecting surface and from the reflecting surface to the source.Speed given is = 360 m/sCalculate the distance Speed = distance / time= > 360 m/s = 2 d / 0.5 s= > 2 d = 360 m/s × 0.5 s= > 2 d = 180 m= > d = 180 m / 2= > d =90 mSorry if wrong =_= |
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