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Height of the image when the 2cm object kept on the Centre of curvature of a concave mirror is |
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Answer» Given that,Focal length f= 2R RADIUS of curvature R=30Object distance u=10cmHeight of object h o =2cmFrom the mirror formula, F1 = v1 + u1 − v1 = u1 − f1 − v1 = 101 − 302 − v1 = 303−2 v=−30cmNow, the MAGNIFICATION is m= u−v m= 1030 m=3 Now, the height of image m= h o h i 3= 2h i h i =6cm Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3 |
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