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Heat of fusion of benzene is 10 J at 0^oC, if Cp of solid benzene is 10 J/^oC, and that of liquid benzene is 5 J/^oC what is the enthalpy change of benzene from – 10^oC to 10^oC?(a) 160 J(b) 200 J(c) 240 J(d) 300 J |
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Answer» Correct option is (a) 160 J Best explanation: ∆H = -10∫^010.dT + 10 + 0∫^105.dT = 10*10 + 10 + 5*10 = 160 J. |
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