1.

Heat of formation of CH_(4) are: If given heat: C(s)+ O_(2)(g) rarr CO_(2) (g) ""DeltaH =-394 KJ 2H_(2) (g)+ O_(2)(g) rarr 2H_(2)O(l) rarr 2H_(2)O(l) ""DeltaH =-394 KJ CH_(4)(g) + 2O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(l) "" DeltaH =- 394 KJ

Answer»

`-70 KJ`
`-16.7 Kcal`
`-244 KJ`
`-50 Kcal`

Solution :`(1) + (2)-(3)`
`DeltaH_("REACTION") =-394 -568+892=-70 KJ`
`""=-16.607Kcal.`


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