हे» sin? (2xyf1—x?) =2 cos" % (z—l"< g – InterviewSolution

1.

हे» sin? (2xyf1—x?) =2 cos" % (z—l"< g

Answer»

Let x= cos theta. Then cos^-1x = theta.

sin^-1(2x(sqrt(1-x^2)))= sin^-1(2cos theta(sqrt(1-cos^2theta))) = sin^-1(2cos theta sin theta) = sin^-1(sin 2theta) = 2theta = 2cos^-1x

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