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HCF, LCM of two numbers are 9 and 54 respectively. If one of those two numbers is 18, find the other number. |
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Answer» Given, HCF of two numbers = 9 LCM of two numbers = 54 One of the two numbers a = 18 Then, the other number b = ? We know, that the product of two numbers = LCM × HCF a × b = LCM × HCF 18 × b = 54 × 9 b = \(\frac{54\times9}{18}\) = 27 ∴ The other number = 27 |
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